In the described case, a 12.5 lb cat requires Ketamine at 22 mg/kg IM. If Ketamine is 100 mg/mL, what volume (mL) should be given to achieve the dose?

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Multiple Choice

In the described case, a 12.5 lb cat requires Ketamine at 22 mg/kg IM. If Ketamine is 100 mg/mL, what volume (mL) should be given to achieve the dose?

Explanation:
To find the volume, convert weight to kilograms, calculate the total milligrams needed, and then convert that to milliliters using the concentration. The cat weighs 12.5 lb, which is about 5.67 kg. At 22 mg/kg, the total dose is about 5.67 × 22 ≈ 125 mg. With a Ketamine solution of 100 mg/mL, the required volume is 125 mg ÷ 100 mg/mL = 1.25 mL. Therefore, administer about 1.25 mL IM.

To find the volume, convert weight to kilograms, calculate the total milligrams needed, and then convert that to milliliters using the concentration.

The cat weighs 12.5 lb, which is about 5.67 kg. At 22 mg/kg, the total dose is about 5.67 × 22 ≈ 125 mg. With a Ketamine solution of 100 mg/mL, the required volume is 125 mg ÷ 100 mg/mL = 1.25 mL. Therefore, administer about 1.25 mL IM.

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